QUESTION IMAGE
Question
complete the table of values for $f(x) = 3x + 5$ and $g(x) = 3(2)^x$.
| $x$ | $f(x)$ | $g(x)$ |
|---|---|---|
| 2 | ||
| 3 | ||
| 4 |
both $f(x)$ and $g(x)$ grow as $x$ gets larger and larger. which function eventually exceeds the other?
- $f(x) = 3x + 5$
- $g(x) = 3(2)^x$
Part 1: Completing the Table of Values
For \( f(x) = 3x + 5 \):
Step 1: When \( x = 1 \)
Substitute \( x = 1 \) into \( f(x) \):
\( f(1) = 3(1) + 5 = 3 + 5 = 8 \)
Step 2: When \( x = 2 \)
Substitute \( x = 2 \) into \( f(x) \):
\( f(2) = 3(2) + 5 = 6 + 5 = 11 \)
Step 3: When \( x = 3 \)
Substitute \( x = 3 \) into \( f(x) \):
\( f(3) = 3(3) + 5 = 9 + 5 = 14 \)
Step 4: When \( x = 4 \)
Substitute \( x = 4 \) into \( f(x) \):
\( f(4) = 3(4) + 5 = 12 + 5 = 17 \)
For \( g(x) = 3(2)^x \):
Step 1: When \( x = 1 \)
Substitute \( x = 1 \) into \( g(x) \):
\( g(1) = 3(2)^1 = 3 \times 2 = 6 \)
Step 2: When \( x = 2 \)
Substitute \( x = 2 \) into \( g(x) \):
\( g(2) = 3(2)^2 = 3 \times 4 = 12 \)
Step 3: When \( x = 3 \)
Substitute \( x = 3 \) into \( g(x) \):
\( g(3) = 3(2)^3 = 3 \times 8 = 24 \)
Step 4: When \( x = 4 \)
Substitute \( x = 4 \) into \( g(x) \):
\( g(4) = 3(2)^4 = 3 \times 16 = 48 \)
The completed table is:
| \( x \) | \( f(x) \) | \( g(x) \) |
|---|---|---|
| 2 | 11 | 12 |
| 3 | 14 | 24 |
| 4 | 17 | 48 |
Part 2: Determining Which Function Exceeds the Other
To determine which function eventually exceeds the other, we analyze the growth rates:
- \( f(x) = 3x + 5 \) is a linear function (degree 1 polynomial), so it grows at a constant rate (slope of 3).
- \( g(x) = 3(2)^x \) is an exponential function (base 2 > 1), so it grows at an increasing rate (the rate of growth itself increases as \( x \) increases).
From the table:
- At \( x = 1 \), \( f(1) = 8 \) and \( g(1) = 6 \) ( \( f(x) \) is larger).
- At \( x = 2 \), \( f(2) = 11 \) and \( g(2) = 12 \) ( \( g(x) \) becomes larger).
- For \( x = 3, 4 \), \( g(x) \) is significantly larger than \( f(x) \).
Since exponential functions grow faster than linear functions for large values of \( x \), \( g(x) = 3(2)^x \) will eventually exceed \( f(x) = 3x + 5 \) as \( x \) gets larger and larger.
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(Table Completion):
| \( x \) | \( f(x) \) | \( g(x) \) |
|---|---|---|
| 2 | 11 | 12 |
| 3 | 14 | 24 |
| 4 | 17 | 48 |