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compute by the same - side interior angles postulate, (mangle1 + 68=180…

Question

compute
by the same - side interior angles postulate, (mangle1 + 68=180).
(mangle1 = 180 - 68 = 112)
by the corresponding angles theorem, (angle eabcongangle2) and (angle2congangle3), so (angle3congangle eab) by the transitive property of congruence.
(mangle3 = 68)
interpret
so, (mangle1 = 112) and (mangle3 = 68).
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  1. if (mangle ejf = 56), find (mangle fhk).

Explanation:

Step1: Identify angle - relationship

Assume $\angle EJF$ and $\angle FHK$ are corresponding angles (if the lines are parallel, which is likely based on the context of angle - finding problems).

Step2: Apply corresponding - angles theorem

If two parallel lines are cut by a transversal, corresponding angles are congruent. So $m\angle FHK=m\angle EJF$.

Answer:

$m\angle FHK = 56$