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converting between exponer and logarithmic forms which is the logarithm…

Question

converting between exponer and logarithmic forms
which is the logarithmic form of $25 = 5^2$?
$\log_{5} 2 = 25$
$\log_{2} 5 = 25$
$\log_{25} 2 = 5$
$\log_{5} 25 = 2$

Explanation:

Step1: Recall exponent-log conversion rule

For $b^y = x$, $\log_b x = y$

Step2: Match values to the rule

Here, $b=5$, $y=2$, $x=25$

Step3: Substitute into logarithmic form

$\log_{5} 25 = 2$

Answer:

$\log_{5} 25 = 2$