Question

1. create a punnett square for a cross of a female who is a hemophilia carrier with a normal male. hemophilia is a recessive trait. 9. what are the odds of their daughter having hemophiliac? what about their son? 0% daughters / 50% sons 10. why are males more likely to have hemophilia than females? 11. a blood test is done to see if one of the three men is the father of a child. this child has...

Explanation:

Question 9

Step1: Analyze daughter's genotype

A female carrier has genotype \(X^H X^h\), normal male has \(X^H Y\). Daughters get one \(X\) from each parent. Possible daughter genotypes: \(X^H X^H\) (normal), \(X^H X^h\) (carrier). No \(X^h X^h\) (hemophiliac) possible. So 0% chance.

Step2: Analyze son's genotype

Sons get \(X\) from mother, \(Y\) from father. Mother can give \(X^H\) or \(X^h\). So possible son genotypes: \(X^H Y\) (normal), \(X^h Y\) (hemophiliac). 1 out of 2, so 50% chance.

Hemophilia is X - linked recessive. Males have one X and one Y. If they inherit the recessive allele (\(X^h\)) on their single X, they express hemophilia. Females have two Xs, so they need two recessive alleles (\(X^h X^h\)) to express it, which is less likely as they can be carriers (\(X^H X^h\)) with one normal allele masking the recessive.

Answer:

Daughter: 0% (0 odds), Son: 50% (1/2 odds)

Question 10