Question

1. cross a female who is colorblind with a male with normal color vision. what are the genotypes and phenotypes of their children?

Explanation:

Step1: Determine parental genotypes

Color - blindness is an X - linked recessive trait. A female who is color - blind has the genotype $X^bX^b$ (where $X^b$ represents the color - blind allele on the X - chromosome), and a male with normal color vision has the genotype $X^BY$.

Step2: Set up Punnett - square

The female can only produce gametes with the $X^b$ allele, and the male can produce gametes with either $X^B$ or $Y$. The Punnett - square will have the female gametes along one side ($X^b$ and $X^b$) and the male gametes along the other side ($X^B$ and $Y$).

Step3: Fill in Punnett - square

	$X^B$	$Y$
$X^b$	$X^BX^b$	$X^bY$

Step4: Determine genotypes and phenotypes of offspring

• Genotypes: The genotypes of the offspring are $X^BX^b$ (female carrier) and $X^bY$ (male color - blind).
• Phenotypes: Females are carriers (normal phenotype) and males are color - blind.

Answer:

Genotypes: Females are $X^BX^b$, males are $X^bY$. Phenotypes: Females have normal color vision (carriers), males are color - blind.