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what are the zeros of the polynomial function $g(x) = (x - 1)(x - 2)(x - 3)$?
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the zeros of the function are $x = \square$, $x = \square$ and $x = \square$

Explanation:

Step1: Set polynomial to 0

$g(x) = (x-1)(x-2)(x-3) = 0$

Step2: Apply zero product rule

If $ab=0$, then $a=0$ or $b=0$. So:
$x-1=0$, $x-2=0$, or $x-3=0$

Step3: Solve for $x$

$x=1$, $x=2$, $x=3$

Answer:

$x=1$, $x=2$ and $x=3$