Question

determine if the following system of equations has no solutions, infinitely many solutions or exactly one solution.
$2x + 3y = -1$
$4x + 6y = 1$
answer attempt 1 out of 2
$circ$ infinitely many solutions
$circ$ no solutions
$circ$ one solution
submit answer

Explanation:

Step1: Scale first equation by 2

Multiply $2x + 3y = -1$ by 2:
$$2(2x + 3y) = 2(-1)$$
$$4x + 6y = -2$$

Step2: Compare to second equation

Second equation is $4x + 6y = 1$. Contradiction: $-2
eq 1$.

Answer:

No Solutions