Question

determine values that make the equation true.
$7x^{2}-10x-\square=(\square x-2)(7x+\square)$

Explanation:

Step1: Identify leading coefficient match

The left side has $7x^2$, so the first term of the first binomial must be $1x$ (since $1x \times 7x = 7x^2$).

Step2: Expand the right-hand side

$$(x - 2)(7x + c) = 7x^2 + cx - 14x - 2c = 7x^2 + (c - 14)x - 2c$$

Step3: Match linear terms

Set the coefficient of $x$ equal to $-10$:
$c - 14 = -10$
Solve for $c$: $c = -10 + 14 = 4$

Step4: Find the constant term

Substitute $c=4$ into $-2c$: $-2(4) = -8$

Answer:

The filled equation is $7x^2 - 10x - 8 = (1x - 2)(7x + 4)$, so the missing values are 8, 1, and 4 (in left-to-right order of the boxes).