Question

1. the diagram below shows a happy family of mice, with two parents and four offspring. however, one of the offspring mice is an imposter. the black - fur parent has the genotype ff ee, and the white - fur parent has the genotype ff ee. given these parent genotypes, which offspring mouse could not have been born to these parents? offspring a(ff ee) offspring b(ff ee) offspring c(ff ee) offspring d(ff ee)

Explanation:

Step1: Analyze allele contributions from parents

The black - fur parent with genotype $FF Ee$ can contribute $F$ for the fur - color gene and either $E$ or $e$ for the other gene. The white - fur parent with genotype $ff Ee$ can contribute $f$ for the fur - color gene and either $E$ or $e$ for the other gene.

Step2: Check each offspring genotype possibility

• For offspring A with genotype $Ff Ee$: The $F$ can come from the black - fur parent ($FF Ee$) and $f$ from the white - fur parent ($ff Ee$), and $E$ or $e$ can come from either parent. So this is possible.
• For offspring B with genotype $Ff EE$: The $F$ can come from the black - fur parent ($FF Ee$), $f$ from the white - fur parent ($ff Ee$), and $E$ from either parent. So this is possible.
• For offspring C with genotype $Ff ee$: The $F$ can come from the black - fur parent ($FF Ee$), $f$ from the white - fur parent ($ff Ee$), and $e$ from both parents. So this is possible.
• For offspring D with genotype $ff EE$: Since the black - fur parent has genotype $FF Ee$, it cannot contribute an $f$ allele. So an offspring with genotype $ff EE$ cannot be born from these parents.

Answer:

D. Offspring D ($ff EE$)