Question

difference of perfect squares (level 2)
score: 1/2 penalty: 0.25 off
question
factor completely.
$y^6 - x^4$
answer attempt 1 out of 2

Explanation:

Step1: Identify perfect squares

$y^6 = (y^3)^2$, $x^4 = (x^2)^2$

Step2: Apply difference of squares formula

$a^2 - b^2 = (a - b)(a + b)$, so $(y^3)^2 - (x^2)^2 = (y^3 - x^2)(y^3 + x^2)$

Answer:

$(y^3 - x^2)(y^3 + x^2)$