QUESTION IMAGE
Question
directions: factor each expression. be sure to che
- ( x^2 + 10x + 24 )
- ( 6p^2 - 24p + 24 ) (with handwritten ( 6(p^2 - 4p + 4) ))
- ( 2x^2 - 15x - 8 )
- ( 16w^2 + 8w + 1 )
- ( k^2 - 25 )
- ( 64x^2y - y )
Problem 7: \( x^2 + 10x + 24 \)
Step1: Find two numbers that multiply to 24 and add to 10.
The numbers are 4 and 6, since \( 4 \times 6 = 24 \) and \( 4 + 6 = 10 \).
Step2: Factor the quadratic.
Using the numbers from Step 1, we can write the quadratic as \( (x + 4)(x + 6) \).
Step1: Factor out the greatest common factor (GCF).
The GCF of 6, -24, and 24 is 6. So, factor out 6: \( 6(p^2 - 4p + 4) \).
Step2: Factor the quadratic inside the parentheses.
The quadratic \( p^2 - 4p + 4 \) is a perfect square trinomial, which factors as \( (p - 2)^2 \).
Step3: Combine the factors.
Putting it all together, we get \( 6(p - 2)^2 \).
Step1: Multiply the coefficient of \( x^2 \) and the constant term.
\( 2 \times (-8) = -16 \).
Step2: Find two numbers that multiply to -16 and add to -15.
The numbers are -16 and 1, since \( -16 \times 1 = -16 \) and \( -16 + 1 = -15 \).
Step3: Rewrite the middle term using these numbers.
\( 2x^2 - 16x + x - 8 \).
Step4: Factor by grouping.
Group the first two terms and the last two terms: \( (2x^2 - 16x) + (x - 8) \).
Factor out the GCF from each group: \( 2x(x - 8) + 1(x - 8) \).
Step5: Factor out the common binomial factor.
\( (2x + 1)(x - 8) \).
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\( (x + 4)(x + 6) \)