Question

divide and simplify.
\frac{24m^{2}n^{2}+20m^{2}n - 4mn^{2}}{8m^{2}n^{2}}
\frac{24m^{2}n^{2}+20m^{2}n - 4mn^{2}}{8m^{2}n^{2}}=\frac{3 + 5}{2n}-\frac{1}{2m}
(use integers or fractions for any numbers in the expression.)

Explanation:

Step1: Split the fraction

$\frac{24m^{2}n^{2}+20m^{2}n - 4mn^{2}}{8m^{2}n^{2}}=\frac{24m^{2}n^{2}}{8m^{2}n^{2}}+\frac{20m^{2}n}{8m^{2}n^{2}}-\frac{4mn^{2}}{8m^{2}n^{2}}$

Step2: Simplify each fraction

For $\frac{24m^{2}n^{2}}{8m^{2}n^{2}}$, cancel out common terms: $\frac{24}{8}=3$.
For $\frac{20m^{2}n}{8m^{2}n^{2}}$, cancel out $m^{2}$ and simplify the coefficient: $\frac{20}{8}\cdot\frac{1}{n}=\frac{5}{2n}$.
For $\frac{4mn^{2}}{8m^{2}n^{2}}$, cancel out $4$, $m$ and $n^{2}$: $\frac{1}{2m}$.

Answer:

$3+\frac{5}{2n}-\frac{1}{2m}$