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draw the image of quadrilateral abcd under a translation by 1 unit to t…

Question

draw the image of quadrilateral abcd under a translation by 1 unit to the right and 6 units up.

Explanation:

Step1: Recall translation rule

For a point $(x,y)$ translated 1 unit right and 6 units up, the new - point is $(x + 1,y+6)$.

Step2: Find new coordinates of point A

Point A has coordinates $(0,-4)$. New coordinates are $(0 + 1,-4 + 6)=(1,2)$.

Step3: Find new coordinates of point B

Point B has coordinates $(-6,-2)$. New coordinates are $(-6 + 1,-2 + 6)=(-5,4)$.

Step4: Find new coordinates of point C

Point C has coordinates $(-5,1)$. New coordinates are $(-5 + 1,1 + 6)=(-4,7)$.

Step5: Find new coordinates of point D

Point D has coordinates $(2,-2)$. New coordinates are $(2 + 1,-2 + 6)=(3,4)$.

Step6: Draw new quadrilateral

Plot the new points $(1,2),(-5,4),(-4,7),(3,4)$ and connect them to form the translated quadrilateral.

Answer:

Plot points $(1,2),(-5,4),(-4,7),(3,4)$ and connect them.