Question

the endpoints of $overline{cd}$ are $c(-8, -6)$ and $d(-4, 10)$. the coordinates of the midpoint $m$ of $overline{cd}$ are ( , ).

Explanation:

Step1: Recall mid - point formula

The mid - point formula for two points $(x_1,y_1)$ and $(x_2,y_2)$ is $M(\frac{x_1 + x_2}{2},\frac{y_1 + y_2}{2})$. Here $x_1=-8,y_1 = - 6,x_2=-4,y_2 = 10$.

Step2: Calculate x - coordinate of mid - point

$x=\frac{-8+( - 4)}{2}=\frac{-8 - 4}{2}=\frac{-12}{2}=-6$.

Step3: Calculate y - coordinate of mid - point

$y=\frac{-6 + 10}{2}=\frac{4}{2}=2$.

Answer:

$(-6,2)$