QUESTION IMAGE
Question
b.
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$x^{\circ}=\square^{\circ}$
Step1: Find sum of interior angles of pentagon
The formula for the sum of interior angles of a polygon is \((n - 2)\times180^\circ\), where \(n\) is the number of sides. For a pentagon, \(n = 5\), so the sum is \((5 - 2)\times180^\circ= 540^\circ\).
Step2: Calculate the unknown interior angle
Let the unknown interior angle (adjacent to \(x^\circ\)) be \(y^\circ\). We know four interior angles: \(120^\circ\), \(90^\circ\), \(108^\circ\), \(100^\circ\). So \(120 + 90 + 108 + 100 + y = 540\).
Simplify: \(418 + y = 540\), so \(y = 540 - 418 = 122^\circ\).
Step3: Find \(x\) using linear pair
Since \(y\) and \(x\) form a linear pair, \(y + x = 180\). So \(122 + x = 180\), so \(x = 180 - 122 = 58\).
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