Question

the equation 2(l + w)=100 represents a rectangle with a perimeter of 100 units, a length l, and a width w. move an equation into each box to solve for the length, l, using the steps shown. 2(l + w)=100 (original equation) (division property of equality) (subtraction property of equality) l = 50 + w l = 50 - w l + w = 50 l + w = 200 l = 200 - w

Explanation:

Step1: Divide both sides by 2

Divide the equation $2(L + w)=100$ by 2 on both sides. Using the division - property of equality, we get $\frac{2(L + w)}{2}=\frac{100}{2}$, which simplifies to $L + w = 50$.

Step2: Subtract w from both sides

Using the subtraction - property of equality, subtract $w$ from both sides of the equation $L + w = 50$. So, $L+w - w=50 - w$, and we get $L = 50 - w$.

Answer:

First box: $L + w = 50$
Second box: $L = 50 - w$