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Question
does the equation 4(x - 2) = 4x - 6 have one solution, no solutions, or infinitely many solutions? subtract 4x from each side to rewrite the equation. 4(x - 2) = 4x - 6 4x - 8 = 4x - 6 -4x = -4x \square = \square
Step1: Expand left-hand side
$4(x-2)=4x-8$
Step2: Subtract $4x$ from both sides
$4x-8-4x=4x-6-4x$
Step3: Simplify both sides
$-8=-6$
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The equation has no solutions. The blanks after subtracting $4x$ are filled with $-8$ (left) and $-6$ (right).