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Question
does the equation 4(x - 2) = 4x - 6 have one solution, no solutions, or infinitely many solutions?
4(x - 2) = 4x - 6
4x - \square = 4x - 6
Step1: Expand left-hand side
$4(x-2) = 4x - 8$
Step2: Compare to right-hand side
Set equal to $4x-6$: $4x - 8 = 4x - 6$
Step3: Simplify to check solutions
Subtract $4x$ from both sides: $-8 = -6$
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First, fill the box with 8. The simplified equation results in a false statement ($-8=-6$), so the equation has no solutions.