Question

the equation of line p is y = -9/7x + 2. line q is perpendicular to p. what is the slope of line q? simplify your answer and write it as a proper fraction, improper fraction, or integer.

Explanation:

Step1: Recall perpendicular - slope rule

The product of slopes of two perpendicular lines is - 1. Let the slope of line $p$ be $m_1$ and the slope of line $q$ be $m_2$. So $m_1\times m_2=-1$.

Step2: Identify the slope of line $p$

The equation of line $p$ is $y =-\frac{9}{7}x + 2$, and its slope $m_1=-\frac{9}{7}$.
This In The
1850.10 The following theorem is a The

1. First, we assume that $f$ is a linear function. Let $f(x)$ is a Theven
2. Recall the property of perpendicular lines:

• If two non - vertical lines are perpendicular, the product of their slopes is - 1. Let the slope of line $p$ be $m_1. Let the slope of line $p$ be $m_1$ and the slope of line $q$ be $m_2$.
• Given the equation of line $p$ is in the slope - intercept form $y = -\frac{9}{7}x + 2$.
• The slope of line $p$ is $m_$.
• The slope of line $p$ is $m_1 =-\frac{9}{7}$.

1. Recall the perpendicular - slope relationship:

• For two perpendicular lines with slopes $m_1$ and $m_2$, we have $m_1 \times m_2=-1$.
• We know that $m_1 =-\frac{9}{7
• Solve for the value of $m_2$:

1. First, write the equation based on the P1:

• Given $m_1\times m_2=- 1$,
• Substitute $m_1 =-\frac{9}{7}$ into the equation:
• We have $-\frac{9}{7}\times m_2=-1$.

1. Then, solve for $m_2$:

• Solve the equation $-\frac{9}{7}\times m_2=-1$ for $m_2$.
• Multiply both sides of the equation by $-\frac{7}{9}$ to isolate $m_2$.
• $m_2=\frac{7}{9}$

So the slope of line $q$ is $\frac{7}{9}$.

Answer:

Step1: Recall perpendicular - slope rule

The product of slopes of two perpendicular lines is - 1. Let the slope of line $p$ be $m_1$ and the slope of line $q$ be $m_2$. So $m_1\times m_2=-1$.

Step2: Identify the slope of line $p$

The equation of line $p$ is $y =-\frac{9}{7}x + 2$, and its slope $m_1=-\frac{9}{7}$.
This In The
1850.10 The following theorem is a The

1. First, we assume that $f$ is a linear function. Let $f(x)$ is a Theven
2. Recall the property of perpendicular lines:

• If two non - vertical lines are perpendicular, the product of their slopes is - 1. Let the slope of line $p$ be $m_1. Let the slope of line $p$ be $m_1$ and the slope of line $q$ be $m_2$.
• Given the equation of line $p$ is in the slope - intercept form $y = -\frac{9}{7}x + 2$.
• The slope of line $p$ is $m_$.
• The slope of line $p$ is $m_1 =-\frac{9}{7}$.

1. Recall the perpendicular - slope relationship:

• For two perpendicular lines with slopes $m_1$ and $m_2$, we have $m_1 \times m_2=-1$.
• We know that $m_1 =-\frac{9}{7
• Solve for the value of $m_2$:

1. First, write the equation based on the P1:

• Given $m_1\times m_2=- 1$,
• Substitute $m_1 =-\frac{9}{7}$ into the equation:
• We have $-\frac{9}{7}\times m_2=-1$.

1. Then, solve for $m_2$:

• Solve the equation $-\frac{9}{7}\times m_2=-1$ for $m_2$.
• Multiply both sides of the equation by $-\frac{7}{9}$ to isolate $m_2$.
• $m_2=\frac{7}{9}$

So the slope of line $q$ is $\frac{7}{9}$.