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Question
does the equation $6x + 3 = 5(x + 3)$ have one solution, no solutions, or infinitely many solutions? is inside the parentheses on the right. so, lets start by getting rid of the parentheses to make this equation easier to work with. one way to do this is to distribute the 5 to the $x$ and to the 3. you can think of this as $(5 \cdot x) + (5 \cdot 3)$. rewrite the right side. $6x + 3 = 5(x + 3)$ $6x + 3 = \square + \square$
Step1: Distribute 5 to terms inside parentheses
$5(x+3) = 5\cdot x + 5\cdot 3$
Step2: Calculate the products
$5\cdot x = 5x$, $5\cdot 3 = 15$
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$5x + 15$