Question

for $f(x) = 2x - 3x^2$, evaluate $f(-3)$. \
\bigcirc -33 \
\bigcirc 6 \
\bigcirc -21 \
\bigcirc 33

Explanation:

Step1: Substitute \( x = -3 \) into \( f(x) \)

We have \( f(x) = 2x - 3x^2 \), so substitute \( x=-3 \):
\( f(-3)=2\times(-3)-3\times(-3)^2 \)

Step2: Calculate each term

First term: \( 2\times(-3)= -6 \)
Second term: \( (-3)^2 = 9 \), so \( 3\times(-3)^2 = 3\times9 = 27 \)

Step3: Combine the terms

\( f(-3)= -6 - 27 \)
\( f(-3)= -33 \)

Answer:

-33 (corresponding to the first option: -33)