Question

1. evaluate the expression ( 3x - 7 ) when ( x = -2 ).

a) ( -13 )
b) ( -1 )
c) ( 1 )
d) ( 13 )

1. which equation has the solution ( x = -8 )?

a) ( x + 5 = -3 )
b) ( x - 5 = -3 )
c) ( x + 5 = 3 )
d) ( 2x = 16 )

1. what is the first step to solve ( \frac{1}{3}x = 12 )?

a) add ( \frac{1}{3} ) to both sides
b) multiply both sides by ( \frac{1}{3} )
c) multiply both sides by ( 3 )
d) divide both sides by ( 12 )

Explanation:

Step1: Substitute $x=-2$ into $3x-7$

$3(-2) - 7$

Step2: Calculate multiplication first

$-6 - 7$

Step3: Compute final subtraction

$-13$

Step4: Test $x=-8$ in Eq.A

$-8 + 5 = -3$, which is true

Step5: Test $x=-8$ in Eq.B

$-8 - 5 = -13
eq -3$, false

Step6: Test $x=-8$ in Eq.C

$-8 + 5 = -3
eq 3$, false

Step7: Test $x=-8$ in Eq.D

$2(-8) = -16
eq 16$, false

Step8: Isolate $x$ in $\frac{1}{3}x=12$

Multiply by reciprocal of $\frac{1}{3}$ (which is 3)

Answer:

1. A) $-13$
2. A) $x + 5 = -3$
3. C) Multiply both sides by 3