Question

evaluate the following functions.
you get unlimited reattempts.
$f(x) = 7(x - 1)$
$g(x) = -3(x - 6)$
find $f(9) + g(-1)$

Explanation:

Step1: Calculate \( f(9) \)

Substitute \( x = 9 \) into \( f(x)=7(x - 1) \).
\( f(9)=7\times(9 - 1)=7\times8 = 56 \)

Step2: Calculate \( g(-1) \)

Substitute \( x=-1 \) into \( g(x)=-3(x - 6) \).
\( g(-1)=-3\times(-1 - 6)=-3\times(-7)=21 \)

Step3: Calculate \( f(9)+g(-1) \)

Add the results of \( f(9) \) and \( g(-1) \).
\( f(9)+g(-1)=56 + 21=77 \)

Answer:

\( 77 \)