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explain how to plot the point (6, - 3) in a coordinate plane. graph eac…

Question

explain how to plot the point (6, - 3) in a coordinate plane. graph each point on the coordinate plane label the points on the graph. second, tell quadrant or axis. (5, 6) 19) b (0, 4) 20) c (2, - 4) 22) e (-7, 0) 23) f (-5, -3)

Explanation:

Step1: Understand coordinate - plane basics

In a coordinate plane, a point is represented as $(x,y)$. The $x$ - coordinate tells the horizontal position and the $y$ - coordinate tells the vertical position.

Step2: Analyze the $x$ - coordinate of $(6, - 3)$

The $x$ - coordinate of the point $(6,-3)$ is $x = 6$. Starting from the origin $(0,0)$, move 6 units to the right along the $x$ - axis.

Step3: Analyze the $y$ - coordinate of $(6, - 3)$

The $y$ - coordinate is $y=-3$. From the position reached in Step 2 (6 units to the right of the origin), move 3 units down along the $y$ - axis. Then mark the point.

Step4: Determine the quadrant

Since $x>0$ and $y < 0$, the point $(6,-3)$ lies in the fourth quadrant.

Answer:

To plot the point $(6,-3)$: start at the origin, move 6 units to the right along the $x$ - axis and then 3 units down along the $y$ - axis. The point lies in the fourth quadrant.