Question

factor completely.
$8j^3 + 16j^2 + 5j + 10$

Explanation:

Step1: Group terms into pairs

Group first two and last two terms:
$(8j^3 + 16j^2) + (5j + 10)$

Step2: Factor out GCF from each pair

Factor $8j^2$ from first group, 5 from second:
$8j^2(j + 2) + 5(j + 2)$

Step3: Factor out common binomial

Factor $(j+2)$ from both terms:
$(j + 2)(8j^2 + 5)$

Answer:

$(j + 2)(8j^2 + 5)$