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factor completely. $8w^{2}-8w - 9w^{3}+9w^{4}$

Question

factor completely.
$8w^{2}-8w - 9w^{3}+9w^{4}$

Explanation:

Step1: Rearrange terms by degree

$$9w^4 - 9w^3 + 8w^2 - 8w$$

Step2: Group terms for factoring

$$(9w^4 - 9w^3) + (8w^2 - 8w)$$

Step3: Factor out GCF from each group

$$9w^3(w - 1) + 8w(w - 1)$$

Step4: Factor out common binomial

$$(w - 1)(9w^3 + 8w)$$

Step5: Factor GCF from second term

$$(w - 1)w(9w^2 + 8)$$

Step6: Rewrite in standard order

$$w(w - 1)(9w^2 + 8)$$

Answer:

$w(w - 1)(9w^2 + 8)$