QUESTION IMAGE
Question
factor completely. \\( r^2 + 2r + 1 \\)
Step1: Recall perfect square formula
The perfect square trinomial formula is \(a^2 + 2ab + b^2=(a + b)^2\). For the expression \(r^2+2r + 1\), we can identify \(a = r\) and \(b = 1\) since \(a^2=r^2\), \(2ab = 2\times r\times1=2r\) and \(b^2 = 1^2 = 1\).
Step2: Apply the formula
Using the perfect square trinomial formula \(a^2+2ab + b^2=(a + b)^2\) with \(a=r\) and \(b = 1\), we get \(r^2+2r + 1=(r + 1)^2\).
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\((r + 1)^2\)