Question

factor by grouping.\\(25y^{3}+20y^{2}-5y - 4\\)

Explanation:

Step1: Group the terms

Group the first two terms and the last two terms: $(25y^{3}+20y^{2})+(-5y - 4)$

Step2: Factor out GCF from each group

Factor out $5y^{2}$ from the first group and $-1$ from the second group: $5y^{2}(5y + 4)-1(5y + 4)$

Step3: Factor out the common binomial factor

Factor out $(5y + 4)$ from both terms: $(5y + 4)(5y^{2}-1)$

Answer:

$(5y + 4)(5y^{2}-1)$