Question

in the figure, $overrightarrow{cd}$ and $overrightarrow{cb}$ are opposite rays, and $overrightarrow{ca}$ bisects $angle bce$. if $mangle eca=(14x - 2)^{circ}$ and $mangle acb=(12x + 8)^{circ}$, then $mangle eca=square^{circ}$.

Explanation:

Step1: CA bisects ∠BCE, so ∠ECA=∠ACB

14x - 2 = 12x + 8

Step2: Solve for x

2x = 10 ⇒ x=5

Step3: Calculate m∠ECA

14*5 - 2 = 68

Answer:

68