Question

fill in the value that will make each ordered pair a solution for the given equation.

1. $x + y = 6$

a. $(2, \quad )$
b. $(0, \quad )$
c. $(\quad ,0)$

1. $2x + 4y = 8$

a. $(2, \quad )$
b. $(0, \quad )$
c. $(\quad ,0)$

Explanation:

For Problem 4: $x + y = 6$

Step1: Substitute $x=2$, solve for $y$

$2 + y = 6 \implies y = 6 - 2$

Step2: Substitute $x=0$, solve for $y$

$0 + y = 6 \implies y = 6$

Step3: Substitute $y=0$, solve for $x$

$x + 0 = 6 \implies x = 6$

For Problem 5: $2x + 4y = 8$

Step4: Substitute $x=2$, solve for $y$

$2(2) + 4y = 8 \implies 4 + 4y = 8 \implies 4y = 4 \implies y = \frac{4}{4}$

Step5: Substitute $x=0$, solve for $y$

$2(0) + 4y = 8 \implies 4y = 8 \implies y = \frac{8}{4}$

Step6: Substitute $y=0$, solve for $x$

$2x + 4(0) = 8 \implies 2x = 8 \implies x = \frac{8}{2}$

Answer:

Problem 4

a. $(2, 4)$
b. $(0, 6)$
c. $(6, 0)$

Problem 5

a. $(2, 1)$
b. $(0, 2)$
c. $(4, 0)$