Question

find the area of the figure below, composed of an isosceles trapezoid and one semicircle. rounded to the nearest tenths place

Explanation:

Step1: Calculate trapezoid area

The formula for the area of a trapezoid is $\frac{1}{2} \times (b_1 + b_2) \times h$, where $b_1=10$, $b_2=2$, $h=4$.
$\frac{1}{2} \times (10 + 2) \times 4 = \frac{1}{2} \times 12 \times 4 = 24$

Step2: Calculate semicircle area

The diameter of the semicircle is 2, so radius $r = \frac{2}{2}=1$. The formula for the area of a semicircle is $\frac{1}{2} \times \pi r^2$.
$\frac{1}{2} \times \pi \times 1^2 = \frac{\pi}{2} \approx 1.5708$

Step3: Sum the two areas

Add the area of the trapezoid and the semicircle.
$24 + 1.5708 = 25.5708$

Step4: Round to nearest tenth

Round the total area to one decimal place.
$25.5708 \approx 25.6$

Answer:

25.6