Question

find the area of the figure below, composed of an isosceles trapezoid and one semi - circle. rounded to the nearest tenths place

Explanation:

Step1: Calculate area of trapezoid

The formula for the area of a trapezoid is $A_{t}=\frac{(a + b)h}{2}$, where $a = 8$, $b=2$, and $h = 4$. So $A_{t}=\frac{(8 + 2)\times4}{2}=20$.

Step2: Calculate area of semi - circle

The diameter of the semi - circle is 2, so the radius $r = 1$. The formula for the area of a semi - circle is $A_{s}=\frac{1}{2}\pi r^{2}$. Then $A_{s}=\frac{1}{2}\pi\times1^{2}=\frac{\pi}{2}\approx1.6$.

Step3: Calculate total area

The total area $A=A_{t}+A_{s}=20 + 1.6=21.6$.

Answer:

$21.6$