Question

find the common ratio of the geometric sequence 2, \frac{1}{2}, \frac{1}{8}, \frac{1}{32}, ...

Explanation:

Step1: Divide term2 by term1

$\frac{\frac{1}{2}}{2} = \frac{1}{2} \times \frac{1}{2} = \frac{1}{4}$

Step2: Verify with term3/term2

$\frac{\frac{1}{8}}{\frac{1}{2}} = \frac{1}{8} \times 2 = \frac{1}{4}$

Step3: Verify with term4/term3

$\frac{\frac{1}{32}}{\frac{1}{8}} = \frac{1}{32} \times 8 = \frac{1}{4}$

Answer:

C. $\frac{1}{4}$