Question

find the correct sum. write your answer as a mixed number.
\\(\frac{5}{6} + 2\frac{4}{6} = square \frac{square}{square}\\)

Explanation:

Step1: Add the fractional parts

The fractional parts are $\frac{5}{6}$ and $\frac{4}{6}$. Adding them: $\frac{5}{6} + \frac{4}{6} = \frac{5 + 4}{6} = \frac{9}{6}$

Step2: Simplify the fraction and add the whole number

Simplify $\frac{9}{6}$: $\frac{9}{6} = 1\frac{3}{6}$. Now add the whole number part (2) to 1: $2 + 1 = 3$. The remaining fraction is $\frac{3}{6}$, which can be simplified to $\frac{1}{2}$, but since we started with denominator 6, we can also keep it as $\frac{3}{6}$ (or simplify later). Wait, actually, let's do it step by step. Wait, the original mixed number is $2\frac{4}{6}$, so when we add $\frac{5}{6}$ to $2\frac{4}{6}$, we can add the fractions first: $\frac{5}{6} + \frac{4}{6} = \frac{9}{6} = 1\frac{3}{6}$. Then add the whole number 2: $2 + 1\frac{3}{6} = 3\frac{3}{6}$. Simplify $\frac{3}{6}$ to $\frac{1}{2}$, so $3\frac{1}{2}$, but let's check the denominators. Wait, maybe we can do it as: $2\frac{4}{6} + \frac{5}{6} = 2 + (\frac{4}{6} + \frac{5}{6}) = 2 + \frac{9}{6} = 2 + 1\frac{3}{6} = 3\frac{3}{6} = 3\frac{1}{2}$. But let's see the format. The problem has a mixed number with numerator and denominator. Wait, maybe we don't simplify the fraction yet. So $\frac{9}{6} = 1\frac{3}{6}$, then add 2: $2 + 1\frac{3}{6} = 3\frac{3}{6}$. So the whole number part is 3, numerator 3, denominator 6. (We can also simplify $\frac{3}{6}$ to $\frac{1}{2}$, but let's check the original denominators. The problem's fractions have denominator 6, so maybe we keep it as 6 for now.)

Answer:

The sum is $3\frac{3}{6}$ (or simplified to $3\frac{1}{2}$, but based on the denominator 6, it's $3\frac{3}{6}$). So the whole number is 3, numerator is 3, denominator is 6.