Question

find the derivative.
$\frac{d}{dx}(8sqrt{x}-\frac{7}{x})$
$\frac{d}{dx}(8sqrt{x}-\frac{7}{x})=square$

Explanation:

Step1: Rewrite terms

$8\sqrt{x}=8x^{\frac{1}{2}}$, $\frac{7}{x}=7x^{- 1}$

Step2: Apply derivative rules

$\frac{d}{dx}(8x^{\frac{1}{2}}-7x^{-1})=8\times\frac{1}{2}x^{-\frac{1}{2}}-7\times(-1)x^{-2}$

Step3: Simplify

$4x^{-\frac{1}{2}} + 7x^{-2}=\frac{4}{\sqrt{x}}+\frac{7}{x^{2}}$

Answer:

$\frac{4}{\sqrt{x}}+\frac{7}{x^{2}}$