Question

find the derivative of the following function
$g(w)=e^{w}-e^{9}+4$
$g(w)=\square$

Explanation:

Step1: Recall derivative rules

The derivative of $e^x$ with respect to $x$ is $e^x$, and the derivative of a constant is 0.

Step2: Differentiate each term

The derivative of $e^w$ with respect to $w$ is $e^w$. The derivative of $-e^9$ (a constant) with respect to $w$ is 0, and the derivative of 4 (a constant) with respect to $w$ is 0.
So $g'(w)=e^w+0 + 0$.

Answer:

$e^w$