Question

find the discriminant.
4x² + 4x + 1 = 0

Explanation:

Step1: Recall discriminant formula

For a quadratic equation $ax^{2}+bx + c = 0$, the discriminant $\Delta=b^{2}-4ac$.

Step2: Identify coefficients

In the equation $4x^{2}+4x + 1 = 0$, $a = 4$, $b = 4$, $c = 1$.

Step3: Calculate discriminant

$\Delta=(4)^{2}-4\times4\times1$
$=16 - 16$
$=0$

Answer:

$0$