Question

find the discriminant.
8t^{2}+7t + 9 = 0

Explanation:

Step1: Recall discriminant formula

For a quadratic equation $ax^{2}+bx + c = 0$, the discriminant $\Delta=b^{2}-4ac$.

Step2: Identify coefficients

In the equation $8t^{2}+7t + 9 = 0$, we have $a = 8$, $b = 7$, and $c = 9$.

Step3: Calculate discriminant

$\Delta=7^{2}-4\times8\times9=49 - 288=-239$

Answer:

$-239$