Question

find the distance, d, of $overline{ab}$. a = (5, 4) b = (14, 0) d = ? d = $sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}$ round to the nearest tenth.

Explanation:

Step1: Identify coordinates

Let $(x_1,y_1)=(5,4)$ and $(x_2,y_2)=(14,0)$.

Step2: Substitute into distance formula

$d = \sqrt{(14 - 5)^2+(0 - 4)^2}=\sqrt{9^2+( - 4)^2}=\sqrt{81 + 16}=\sqrt{97}$.

Step3: Calculate and round

$\sqrt{97}\approx9.8$.

Answer:

$9.8$