Question

find the distance between x (-3,5) and y (4,2). round to the nearest tenth, if necessary.

Explanation:

Step1: Identify distance formula

The distance formula between two points $(x_1,y_1)$ and $(x_2,y_2)$ is $d = \sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}$.

Step2: Substitute values

Here, $x_1=-3,y_1 = 5,x_2 = 4,y_2=2$. So $d=\sqrt{(4-(-3))^2+(2 - 5)^2}=\sqrt{(4 + 3)^2+(2-5)^2}=\sqrt{7^2+(-3)^2}=\sqrt{49 + 9}=\sqrt{58}$.

Step3: Calculate and round

$\sqrt{58}\approx7.6$.

Answer:

$7.6$