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find the distance between c(2,4) and d(5,7). round to the nearest tenth…

Question

find the distance between c(2,4) and d(5,7). round to the nearest tenth, if necessary.

Explanation:

Step1: Recall distance formula

The distance formula between two points $(x_1,y_1)$ and $(x_2,y_2)$ is $d = \sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}$. Here, $x_1 = 2,y_1 = 4,x_2=5,y_2 = 7$.

Step2: Substitute values

$d=\sqrt{(5 - 2)^2+(7 - 4)^2}=\sqrt{3^2+3^2}=\sqrt{9 + 9}=\sqrt{18}$.

Step3: Simplify and round

$\sqrt{18}\approx4.2426\approx4.2$.

Answer:

$4.2$