Question

find the distance between the two points rounding to the nearest tenth (if necessary).

(-3, 5) and (1, -1)

Explanation:

Step1: Recall distance formula

The distance $d$ between two points $(x_1,y_1)$ and $(x_2,y_2)$ is $d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Step2: Assign values to variables

Let $(x_1,y_1)=(-3,5)$ and $(x_2,y_2)=(1,-1)$. Substitute into formula:
$d=\sqrt{(1-(-3))^2+(-1-5)^2}$

Step3: Simplify inside the square root

Calculate differences first:
$1-(-3)=4$, $-1-5=-6$
Then square the results:
$4^2=16$, $(-6)^2=36$
Sum the squares:
$16+36=52$
So $d=\sqrt{52}$

Step4: Calculate and round

$\sqrt{52}\approx7.211$, round to nearest tenth: $7.2$

Answer:

$7.2$