Question

find the distance between the two points rounding to the nearest tenth (if necessary). (4, -8) and (6, -1)

Explanation:

Step1: Recall distance formula

The distance formula between two points $(x_1,y_1)$ and $(x_2,y_2)$ is $d = \sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}$. Here, $x_1 = 4,y_1=-8,x_2 = 6,y_2=-1$.

Step2: Substitute values

$d=\sqrt{(6 - 4)^2+((-1)-(-8))^2}=\sqrt{(2)^2+(7)^2}$.

Step3: Calculate squares

$d=\sqrt{4 + 49}=\sqrt{53}$.

Step4: Approximate value

$\sqrt{53}\approx7.3$.

Answer:

$7.3$