Question

find each difference.
$(-6s^{2}+12s - 8)-(3s^{2}+8s - 6)=$
$-9s^{2}+4s - 14$
$-9s^{2}+4s - 2$
$-9s^{2}+20s - 14$
$-9s^{2}+20s - 2$
complete
$(5a^{2}+4ab - 3b^{2})-(-5ab + 4b^{2}+3a^{2})=$$\square a^{2}+\square ab+(\square b^{2})$
done

Explanation:

Step1: Distribute the negative sign

$(-6s^2 + 12s - 8) - 3s^2 - 8s + 6$

Step2: Combine like $s^2$ terms

$-6s^2 - 3s^2 = -9s^2$

Step3: Combine like $s$ terms

$12s - 8s = 4s$

Step4: Combine constant terms

$-8 + 6 = -2$

Step5: Distribute negative sign (second problem)

$(5a^2 + 4ab - 3b^2) + 5ab - 4b^2 - 3a^2$

Step6: Combine like $a^2$ terms

$5a^2 - 3a^2 = 2a^2$

Step7: Combine like $ab$ terms

$4ab + 5ab = 9ab$

Step8: Combine like $b^2$ terms

$-3b^2 - 4b^2 = -7b^2$

Answer:

1. $-9s^2 + 4s - 2$
2. $2a^2 + 9ab + (-7b^2)$