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find the equation of the line that contains the point (-2, -5) and is p…

Question

find the equation of the line that contains the point (-2, -5) and is perpendicular to the line x = 5. write the line in slope - intercept form, if possible. graph the lines.
the equation of the perpendicular line in slope - intercept form is y = - 5
use the graphing tool to graph the equations.
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Explanation:

Step1: Analyze the given line

The line $x = 5$ is a vertical line. A line perpendicular to a vertical line is a horizontal line.

Step2: Find the equation of the perpendicular line

The equation of a horizontal line is of the form $y = k$, where $k$ is a constant. The line passes through the point $(-2,-5)$. For a horizontal line passing through $(x_0,y_0)=(-2,-5)$, the $y -$coordinate of every point on the line is the same as the $y -$coordinate of the given point. So the equation of the line is $y=-5$.

Answer:

$y = - 5$