Question

a) $y = 6x - 4$
b) $55 = 6 + d^2$
c) $(4 \cdot 3b) + (8 \div 2c)$
if $f(x) = -4x + 7$
find $f(2)$
find $f(-3)+1$
if $f(x) = 2x - 3$
find $f(1)$

Explanation:

1. Find \( f(2) \) when \( f(x) = -4x + 7 \)

Step1: Substitute \( x = 2 \) into \( f(x) \)

\( f(2) = -4(2) + 7 \)

Step2: Calculate the value

First, calculate \( -4(2) = -8 \), then \( -8 + 7 = -1 \)

Step1: Substitute \( x = -3 \) into \( f(x) \)

\( f(-3) = -4(-3) + 7 \)

Step2: Calculate \( f(-3) \)

First, \( -4(-3) = 12 \), then \( 12 + 7 = 19 \)

Step3: Add 1 to \( f(-3) \)

\( 19 + 1 = 20 \)

Step1: Substitute \( x = 1 \) into \( f(x) \)

\( f(1) = 2(1) - 3 \)

Step2: Calculate the value

\( 2(1) = 2 \), then \( 2 - 3 = -1 \)

Answer:

\( -1 \)

2. Find \( f(-3) + 1 \) when \( f(x) = -4x + 7 \)