Question

find the length of side $x$ to the nearest tenth.
(there is a right triangle with angles 30°, 60°, and 90°, hypotenuse length √5, and one leg length $x$)
answer attempt 1 out of 2
$x = $ input box submit a

Explanation:

Step1: Identify trigonometric ratio

For the 30° angle, side $x$ is opposite, and the hypotenuse is $\sqrt{5}$. Use sine:
$\sin(30^\circ) = \frac{x}{\sqrt{5}}$

Step2: Solve for $x$

Substitute $\sin(30^\circ)=\frac{1}{2}$, rearrange:
$x = \sqrt{5} \times \sin(30^\circ) = \sqrt{5} \times \frac{1}{2}$

Step3: Calculate and round

Compute value, round to nearest tenth:
$x = \frac{\sqrt{5}}{2} \approx \frac{2.236}{2} \approx 1.1$

Answer:

$1.1$