Question

find the limit.
lim(x→0) (x^3 - 6x + 8)/(x - 2)
does not exist
-4
0
4

Explanation:

Step1: Substitute x = 0

Substitute \(x = 0\) into \(\frac{x^{3}-6x + 8}{x - 2}\).
We get \(\frac{0^{3}-6\times0 + 8}{0 - 2}\).

Step2: Simplify the expression

\(\frac{0 - 0+8}{-2}=\frac{8}{-2}=-4\)

Answer:

-4