QUESTION IMAGE
Question
find the measure of each interior angle and each exterior angle of a regular 12-gon (a twelve-sided polygon).
measure of each interior angle = \\(\square^\circ\\)
measure of each exterior angle = \\(\square^\circ\\)
Step1: Find the sum of interior angles
The formula for the sum of interior angles of a polygon is \((n - 2)\times180^\circ\), where \(n\) is the number of sides. For a 12 - gon, \(n = 12\). So the sum of interior angles is \((12 - 2)\times180^\circ=10\times180^\circ = 1800^\circ\).
Step2: Find each interior angle
Since it is a regular polygon, all interior angles are equal. So each interior angle \(=\frac{(n - 2)\times180^\circ}{n}\). Substituting \(n = 12\), we get \(\frac{1800^\circ}{12}=150^\circ\).
Step3: Find each exterior angle
The sum of exterior angles of any polygon is \(360^\circ\). For a regular polygon, each exterior angle \(=\frac{360^\circ}{n}\). Substituting \(n = 12\), we get \(\frac{360^\circ}{12}=30^\circ\).
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Measure of each interior angle \(=\boxed{150}\)°
Measure of each exterior angle \(=\boxed{30}\)°