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Question
find the measure of the exterior angle shown. lock 4 (screen will be blank until lock 3 is unlocked) 1) triangle with 39°, (x + 34)°, 2x° 2) triangle with 71°, (x - 6)°, 2x° 3) triangle with x°, (2x + 48)°, (4x + 18)° (exterior angle) 4) triangle with x°, (x + 85)°, (x - 7)° #1#2#3#4 73:a 130:b 138:c 34:d 35.6:f 30:g 146:h 65:i
Problem 1:
Step1: Recall exterior angle theorem
The exterior angle of a triangle is equal to the sum of the two non - adjacent interior angles. So, \(2x=(x + 34)+39\)
Step2: Solve for x
Simplify the right - hand side: \(2x=x + 73\)
Subtract \(x\) from both sides: \(2x-x=x + 73-x\), so \(x = 73\)
Step3: Find the exterior angle
The exterior angle is \(2x\), substitute \(x = 73\) into \(2x\): \(2\times73 = 146\)
Step1: Apply exterior angle theorem
The exterior angle \(2x\) is equal to the sum of the two non - adjacent interior angles. So, \(2x=(x - 6)+71\)
Step2: Solve for x
Simplify the right - hand side: \(2x=x + 65\)
Subtract \(x\) from both sides: \(2x-x=x + 65-x\), so \(x = 65\)
Step3: Find the exterior angle
The exterior angle is \(2x\), substitute \(x = 65\) into \(2x\): \(2\times65=130\)
Step1: Use exterior angle theorem
The exterior angle \((4x + 18)\) is equal to the sum of the two non - adjacent interior angles. So, \(4x+18=x+(2x + 48)\)
Step2: Simplify the equation
Simplify the right - hand side: \(4x+18=3x + 48\)
Subtract \(3x\) from both sides: \(4x-3x+18=3x-3x + 48\), so \(x+18 = 48\)
Subtract 18 from both sides: \(x+18 - 18=48 - 18\), so \(x = 30\)
Step3: Find the exterior angle
Substitute \(x = 30\) into \(4x + 18\): \(4\times30+18=120 + 18=138\)
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